5w^2-55w-30=0

Solution for 5w^2-55w-30=0 equation:

5w^2-55w-30=0

a = 5; b = -55; c = -30;
Δ = b2-4ac
Δ = -552-4·5·(-30)
Δ = 3625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3625}=\sqrt{25*145}=\sqrt{25}*\sqrt{145}=5\sqrt{145}$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-55)-5\sqrt{145}}{2*5}=\frac{55-5\sqrt{145}}{10}
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-55)+5\sqrt{145}}{2*5}=\frac{55+5\sqrt{145}}{10}
$